Find the value to three places of decimals; of `sqrt15`. It is given that `sqrt(2)=1. 414 ,sqrt(3)=1. 732 ,sqrt(10)=3. 162a n dsqrt(5)=2. 236` (approx.).

Find the value to three places of decimals; of sqrt(15. It is ) given that sqrt(2)=1.414,sqrt(3)=1.732,sqrt(10)=3.162and sqrt(5)=2.236 (approx.).

Find the value to three places of decimals; of each of the following.It is given the sqrt(2)=1.414,sqrt(3)=1.732,sqrt(10)=3.162 and sqrt(5)=2.236( approx.).1.)(sqrt(2)+1)/(sqrt(5))

Find the value of three places of decimals; of each of the following.It is given that sqrt(2)=1.414,sqrt(3)=1.732,sqrt(10)=3.162 and sqrt(5)=2.236( approx ).(sqrt(2)+1)/(sqrt(5)) (ii) (2-sqrt(3))/(sqrt(3))( iii) (sqrt(10)-sqrt(5))/(sqrt(2))

Find the value of three places of decimals, of each of following: It is given that sqrt(2)=1. 414 ,\ sqrt(3)=1. 732 ,\ sqrt(10)=3. 162 and sqrt(5)=2. 236 (approx). (i) 1/(sqrt(2)) (ii) 1/(sqrt(3)) (iii) 1/(sqrt(10))

Find the value to three places of decimals, of sqrt(10) : It is given that sqrt(2)=1. 414 ,sqrt(3)=1. 732 , and sqrt(5)=2. 236 (approx.)

Find the value of three places of decimals; of each of the following. It is given that sqrt(2)=1. 414 ,\ sqrt(3)=1. 732 ,\ sqrt(10)=3. 162 and sqrt(5)=2. 236 (approx). (sqrt(2)+1)/(sqrt(5)) (ii) (2-sqrt(3))/(sqrt(3)) (iii) (sqrt(10)-\ sqrt(5))/(sqrt(2))

Find the value of three places of decimals,of each of following: It is given that sqrt(2)=1.414,sqrt(3)=1.732,sqrt(10)=3.162 and sqrt(5)=2.236( approx )*(1)/(sqrt(2))( ii) (1)/(sqrt(3)) (iii) (1)/(sqrt(10))

Find the value to three places of decimals,of sqrt(10): It is given that sqrt(2)=1.414,sqrt(3)=1.732, and sqrt(5)=2.236 (approx.)

Find the value to three places of decimals of each of the following. It is given that sqrt(2)=1. 414 ,\ \ sqrt(3)=1. 732\ ,\ \ \ sqrt(5)=2. 236 and sqrt(10)\ =\ \ 3. 162 i) (sqrt(5)+1)/(sqrt(2)) (ii) (sqrt(10)+\ sqrt(15))/(sqrt(2))

Find the value to three places of decimals of each of the following. It is given that sqrt(2)=1. 414 ,\ \ sqrt(3)=1. 732\ ,\ \ \ sqrt(5)=2. 236 and sqrt(10)\ =\ \ 3. 162 (i) (2+\ sqrt(3))/3 (ii) (sqrt(2)-\ 1)/(sqrt(5))