If `a-8=b` , then determine the value of `|a-b|-|b-a|` . (a) 0 (b) 2 (c) 4 (d) 16

If a=7, b=5, c=3, then the value of a^2+b^2+c^2-a b-b c-c a i s -12 (b) 0 (c) 8 (d) 12

If a=7,\ b=5,\ c=3, then the value of a^2+b^2+c^2-a b-b c-c a\ i s -12 (b) 0 (c) 8 (d) 12

If a b+b c+c a=0 , then what is the value of (1/(a^2-b c)+1/(b^2-c a)+1/(c^2-a b)) ? (a) 0 (b) 1 (c) 3 (d) a+b+c

If [(2a+b,a-2b),(5c-d,4c+3d)]=[(4,-3),(11,24)] then the value of a+b-c+2d is (a) 8 (b) 10 (c) 4 (d) -8

Using the factor theorem it is found that a+b , b+c and c+a are three factors of the determinant |[-2a, a+b ,a+c],[ b+a,-2b,b+c],[c+a, c+b, -2c]|dot The other factor in the value of the determinant is (a) 4 (b) 2 (c) a+b+c (d) none of these

The value of the log_(2)16 is a.(1)/(8) b.8 c.4 d.16

If 2a+b+3c=1 and a>0,b>0,c>0 then the greatest value of a^(4)b^(2)c^(2) is (1)/(9.4^(8)) b.(1)/(9.4^(5)) c.(1)/(9^(4).4^(8)) d.(1)/(9^(4).4)

If a+b+c=0 and a^2+b^2+c^2=16 , find the value of a b+b c+c a

If 2 is a root of the equation x^2+b x+12=0 and the equation x^2+b x+q=0 has equal roots, then q= (a) 8 (b) -8 (c) 16 (d) -16