`root(5)(0.03125)=`

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Convert (0.03125)_(10) to base 16.

The asscending order of (2.89)^(0.5) , 2-(0.5)^2 , sqrt3 and root(3)(0.008) is

(root(3)(a^2).root(3)(a))/(root(5)(a^5)) =

Convert (0.3125)_(10) to binary equivalent.

The value of (0.03125)^(-2/5) is a.4 b.12 c.9 d.31.25

After simplification, numbers of zeroes before first significant digit of (0.03125/25) is "_______" .