`tanalpha.tan(60^@-alpha).tan(60^@+alpha)=tan3alpha`

tan alpha*tan(60^(@)-alpha)*tan(60^(@)+alpha)=tan3 alpha

Sum the series tan alpha tan (alpha+beta)+tan(alpha+beta)+tan(alpha+2beta)+tan(alpha+2beta)tan(alpha+3beta)+… to n terms

Sum the series tan alpha tan (alpha+beta)+tan(alpha+beta)+tan(alpha+2beta)+tan(alpha+2beta)tan(alpha+3beta)+… to n terms

Prove that, tan 8alpha - tan 5 alpha - tan 3 alpha = tan 8alpha tan 5 alpha tan 3 alpha

If 4n alpha = pi , then the value of tanalpha*tan2alpha*tan3alpha …..tan(2n-2)alphatan(2n-1)alpha is:

If alpha=(2 pi)/(7), then tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha

Show that tan8alpha-tan5alpha-tan3alpha=tan8alphatan5alphatan3alpha

If alpha=(2 pi)/(7) then tan alpha tan^(7)2 alpha+tan2 alpha tan4 alpha+tan2 alpha tan4 alpha=