consider two curves `ax^2+4xy+2y^2+x+y+5=0` and `ax^2+6xy+5y^2+2x+3y+8=0` these two curves intersect at four cocyclic points then find out `a`

If the curves ax^2+4xy+2y^2+x+y+5=0 and ax^2+6xy+5y^2+2x+3y+8=0 intersect at four concyclic points then the value of a is

The two curves x^(3) - 3xy^(2) + 2 = 0 and 3x^2y - y^(3) = 2

The two curves x^(3) - 3xy^(2) +2 = 0 and 3x^(2)y-y^(3) = 2

The two curves x^(3) - 3xy^(2) + 2 = 0 and 3x^(2) y - y^(3) = 2

Consider the curves x^(2)+y^(2)=1 and 2x^(2)+2xy+y^(2)-2x-2y=0. These curves intersect at two points (1,0) and (alpha,beta). Find 5(alpha+beta).

The two curves x^3-3xy^2+2=0 and 3x^2y-y^3=2

The two curves x^(3)-3xy^(2)+5=0 and 3x^(2)y-y^(3)-7=0