x+(1)/(x)=3" इक."x^(5)+(1)/(x^(5))-9." Come on "pi" ? "

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(x)/(x^(2)-5x+9)<=1

If 1/(x^2+5)=1/9 then x=

(1) / (2x-3) + (1) / (x-5) = 1 (1) / (9)

int((1-x^(5))^(3/5))/(x^(9))dx" equals "

If f(x)=(x^(9)-3x^(5)+7x^(3)-x+1)/(cos^(2)x) ,then int_(-pi/4)^( pi/4)f(x)dx=

(1-5x)(9x+1)=……

(3x-5)/(7x-5)-(1)/(9)=03x517x-59

If 3x - (1)/(3x ) =5 , find : (i) 9x^(2) + (1)/( 9x^2)