if `f(x)={3^(-x)-1` for `-1&lex<0` and `tan(x/2)` for `0<=x<=pi` and `x/(x^2-2)` for `pi<=x<=6` then `sqrt(f(0)+f(pi/6)+1/5f(5)-1/23) =`

If f(x) = {{:(3^(-x)+1, for, -1 le x lt 0),(tan(x//2), for, 0 le x le pi),(x/(x^(2)-2) ,for, pi le x le 6):} , then sqrt(f(0) + f(pi//6) + 1/5f(5) -1/23)= ……………..

If f(x)=3^(-x)-1 , for -1 le x lt0, =tan(x//2), " for "0lexltpi =(x)/(x^(2)-2)," for "pilexlt6, then f(-1)+f(pi//6)+f(5)=

If f (x) = sin (2x ^(2) -2 [x]) for 0 lt x lt 1, then f ' ((sqrtpi)/(2))=

If f(x)=(25-x^(4))^(1//4) for 0 lt x lt sqrt5 then f(f((1)/(2)))=

If f(x)=(25-x^(4))^(1//4) for 0 lt x lt sqrt5 then f(f((1)/(2)))=

f(x)={(atan^(-1)(1/(x-4)), if 0<=x<4), (btan^(-1)(2/(x-4)), if 4 < x < 6), (sin^(-1)(7-x)+a pi/4, if 6<=x<=9):} and f(4)=pi/2 is continuous on [0, 8] then (a, b)= (i)(1,1) (ii) (1,-1) (iii)(-1,1) (iv) (-1,-1)

If f(x)={:{((sin 2x)/(sqrt(1-cos 2x))", for " 0 lt x lt pi/2),((cos x)/(pi-2x)", for " pi/2 lt x lt pi):} , then

If f(x)={:{((sin 2x)/(sqrt(1-cos 2x))", for " 0 lt x lt pi/2),((cos x)/(pi-2x)", for " pi/2 lt x lt pi):} , then

If f(x)={:{((sin2x)/(sqrt(1-cos2x))", for " 0 lt x le pi/2),((cos x)/(pi-2x)", for "pi/2 lt x le pi):}