[" The equation of tangent to the curve "],[y=x^(2)+4x+1" at "(-1,-2)" is "]

The equation of tangent to the curve y= x^2 +4x+ 1 at (-1, 1) is...... A) 2x-y+3=0 B) 2x+y-5=0 C) 2x-y-1 =0 D) x+y-1 =0

The equation of the tangent to the curve y=4xe^(x) at (-1,(-4)/e) is

The equation of tangent to the curve y=4 xe^(x) at (-1,(-4)/(e )) is

The equation of the tangent to the curve y=x^3+1 at (1,2) is

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equation of the tangent of the curve y=3x^(2) at (1, 1).

The equation of the tangent to the curve y=8/(4+x^2) at x=2 is