" (vii) "(tan x+cot x)/(log_(e)x)

(i) int (1+ tan x)/(x +log sec x) dx (ii) int (1+ cot x)/(x+log sin x) dx.

int_(0)^(pi//2) ln (tan x+ cot x)dx=

y = (tan x) / (x) log_ (e) ((e ^ (x)) / (x ^ (x)))

If f(x)=(tan((pi)/(4)+log_(e)x))^(log_(x)e) is to be made continuous at x=1, then what is the value of f(1)?

int e^(2log_(e)cot x)dx

Prove that: int_(0)^( pi/2)log|tan x+cot x|dx=pi log_(e)2

If "log"_("cos"x) "tan" x + "log"_("sin"x) "cot" x =0, then x =

If "log"_("cos"x) "tan" x + "log"_("sin"x) "cot" x =0, then x =

Range of f(x)=cot^(-1)(log_(e)(1-x^(2))) is