There is some water in a cylindrical vessel of diameter 11 cm .If an iron cube of edge 5.5 cm is entrirely immersed in the water what is the rise in the height of the water in the vessel?

Explanation

Volume of the iron cube `=(5.5)^(3) cm ^(3)`
Volume of the water raised =`(5.5)^(3)cm^(3)`
Let the water rise in the vessel be h cm.
Since level of water is reaiosed due to the iron cube
Volume of raised water = volume of iron cube
`pi((11)/(2))^(2)xxh=(5.5)^(3)`
`(22)/(7)xx(11)/(2)xx(11)/(2)xxh = (55)/(10)xx(55)/(10)xx(55)/(10)xx(2)/(11)xx(2)/(11)xx(7)/(22)=1.75 cm `
Hence rise in the height of the water = 1.75 cm