Find the angle between the large hand and small hand of a clock at the time `4:30`.

Explanation

For small hand
Angle subtends in 12 hours `=360^(@)`
4 hrs 30 min = 4 hrs + `30/60` hrs `=9/2` hrs
Angle subtends in `9/2` hours `=9/2 xx 360^(@)/12=135^(@)`
For large hand
1 hour = angle subtends in 60 min. = `360^(@)`
`rArr` Angle subtends in 30 min. =`180^(@)`
`therefore` Angle between large hand and small hand at the time `4:30`
`=180^(@)- 135^(@)=45^(@)`.