Find the values of the following :
i) `tan (19pi)/3`
ii) `sec(-22pi)/3`

Explanation

i) `tan(19pi)/3= tan(19 xx 180^(@))/(3)`
`=tan(1140^(@))`
`=tan(3 xx 360^(@) +60^(@))`
`=tan60^(@)=sqrt(3)`
ii) `sec(-22pi)/(3)=sec(22pi)/(3)=sec(22 xx 180^(@))/(3)`
`=sec1320^(@)`
`=sec(3 xx 360^(@) + 240^(@))`
`=sec240^(@)=sec(180^(@)+60^(@))`
`=-sec60^(@)=-2` Ans.