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Prove that: tan7A-tan5A-tan2A=tan7Atan...

Prove that:
`tan7A-tan5A-tan2A=tan7Atan5Atan2A`

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To prove the identity \( \tan 7A - \tan 5A - \tan 2A = \tan 7A \tan 5A \tan 2A \), we will use the tangent addition formula and some algebraic manipulation. ### Step 1: Use the tangent addition formula We can express \( \tan 7A \) as: \[ \tan 7A = \tan(5A + 2A) = \frac{\tan 5A + \tan 2A}{1 - \tan 5A \tan 2A} \] ...
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