Find the general value of `theta` from the equation `tantheta+tan2theta+tan3theta=tantheta*tan2theta*tan3theta.`

Explanation

`tantheta+tan2theta+tan3theta=tanthetatan2theta tan3theta`
`rArr tantheta+tan2theta=-tan3theta+tanthetatan2theta tan3theta=-tan3theta(1-tanthetatan2theta)`
`rArr (tantheta+tan2theta)/(1-tanthetatan2theta)=-tan3theta`
`rArr tan(theta+2theta)=-tan3theta`
`rArr tan3theta=-tan3theta`
`rArr 2tan3theta=0`
`rArr tan3theta=0`
`rArr 3theta=npi`
`rArr theta=(npi)/(3)`. Ans.