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Find the general value of theta from the...

Find the general value of `theta` from the equaion `sqrt(3)sintheta+costheta=1`

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`sqrt(3)sintheta+costheta=1`
Divide both sides by `sqrt((sqrt(3))^(2)+1^(2))=2`
`sqrt(3)/2sintheta+1/2costheta=1/2`
`rArr sinpi/3sintheta+cospi/3= cospi/3`
`rArr cos(theta-pi/3)=cospi/3`
`rArr theta-pi/3=2npi+-pi/3`
`rArr theta=2npi+-pi/3+pi/3`
`rArr theta=2npi+(2pi)/(3)` or `theta=2npi`. Ans.
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