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Find the general values of theta from th...

Find the general values of `theta` from the following equations:
`sin4theta-sin2theta=cos3theta`

Text Solution

Verified by Experts

`theta=(2n+1)pi/6, theta=npi+(-1)^(n).pi/6`
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Knowledge Check

  • The general value of theta satisfying the equation 2sin^2 theta-3 sin theta -2=0 is

    A
    `npi+(-1)^(n+1) pi/6`
    B
    `npi+(-1)^n pi/2`
    C
    `npi+(-1)^n(5pi)/6`
    D
    `npi+(-1)^n (7pi)/6`

  • The general value of theta satisfying the equation 2sin^(2) theta -3 sin theta - 2=0 , is .

    A
    `npi + (-1)^(n)(pi)/(6)`
    B
    `npi +(-1)^(n)(pi)/(2)`
    C
    `npi+(-1)^(n)(5pi)/(6)`
    D
    `npi+(-1)^(n)(7pi)/(6)`

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