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sectheta=2/sqrt(3) and cottheta=-sqrt(3)...

`sectheta=2/sqrt(3)` and `cottheta=-sqrt(3)`

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`theta=2npi+pi/6,theta=2npi-pi/2`
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Find the geneal values of theta from the following equations: i) sintheta=sqrt(3)/2 , ii) costheta=1/sqrt(2) , iii) tantheta=sqrt(3) , iv) sectheta=2/sqrt(3) , v) cottheta=1/sqrt(3) , vi) "cosec"theta=sqrt(2)

Find the general values of theta from the following equations: i) sintheta=-sqrt(3)/(2) ii) sectheta=-sqrt(2) iii) cottheta=-1/sqrt(3) , iv) "cosec"theta=-2

cottheta=-sqrt(3) and "cosec"theta=2

Find the general values of theta which satisfy the following equations: i) sintheta=1/sqrt(2) , ii) costheta=1/2 , (iii) tantheta=sqrt(3) , iv) cottheta=1 , v) sectheta=2/sqrt(3) , vi) "cosec"theta=sqrt(2)

Find the most general value of theta which satisfies both the equations, (i) "sin"theta=-(1)/(2),costheta=-(sqrt(3))/(2) (ii) cosectheta=2,cot theta=-sqrt(3) (iii) cottheta=-(1)/(sqrt(3)),cosec theta=-(2)/(sqrt(3))

tantheta+sectheta=sqrt(3)

"cosec"theta+cottheta=sqrt(3)

If sectheta=(2)/(sqrt(3)) ,then find the value of sec2theta .

Solve: sectheta-1=(sqrt(2)-1)tantheta