To solve the equation \( \cot x = -\sqrt{3} \), we can follow these steps:
### Step 1: Identify the angle whose cotangent is \(-\sqrt{3}\)
The cotangent function is negative in the second and fourth quadrants. We know that:
\[
\cot \frac{\pi}{6} = \sqrt{3}
\]
Thus, we can express \(-\sqrt{3}\) as:
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If alpha and beta are the solution of cotx=-sqrt3 in [0, 2pi] and alpha and gamma are the roots of "cosec x"=-2 in [0, 2pi] , then the value of (|alpha-beta|)/(beta+gamma) is equal to
What is/are the solutions of the trigonometric equation cosec x + cotx = sqrt3 . where 0 lt x lt 2x ?
Evaluate: int(sqrt(cotx)-sqrt(tanx))/(1+3sin2x)dx
(2cotx)/(sqrt(x))
(2^(x) cotx)/(sqrt(x))
Let f(x)=min.[tanx, cotx, 1/sqrt(3)], x in [0, pi/2] . If the area bounded by y=f(x) and x-axis is ln(a/b)+pi/(6sqrt(3)) , where a,b are coprimes. Then ab =…..
