In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is `9:1` the ratio of amplitudes of coherent sources is

In young's double slit experiment the ratio of maximum and minimum intensity in the interference experiment is 9:1 .Then The ratio of the amplitudes of coherent sources is :

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1 . The amplitudes of the coherent sources are in the ratio

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1 . The amplitudes of the coherent sources are in the ratio

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1 . The amplitudes of the coherent sources are in the ratio

In Young's experiment ratio of maximum and minimum intensities of fringes is 9: 1. Ratio of amplitude of superposing waves = .....

In Young's double slit experiment the ratio of intensities at the position of maxima and minima is 9/1. the ratio of amplitudes of light waves is

In Young's double slit experiment the ratio of intensities of bright and dark fringes is 9. This means

In the Young's double slit experiment, the ratio of intensities of bright and dark fringes is 9. this means that