`2x^2-5/6x+1/12`

If x= root(3)(5)+2 , then the value of x^3-6x^2+12x-12 is equal to: यदि x= root(3)(5)+2 , x^3-6x^2+12x-12 का मान ज्ञात करें :

2x ^ (2)-(5) / (6) x + (1) / (12)

factorise i) 12x^(2)-7x+1 ii) 6x^(2)+5x-6

Factories: (i) 12x^2-7x+1 (ii) 2x^2+7x+3 (iii) 6x^2+5x-6 (iv) 3x^2-x-4

Factorise:(i) 12 x^2-7x+1 (ii) 2x^2+7x+3 (iii) 6x^2+5x-6 (iv) 3x^2-x-4

Factorise: (i) 12 x^2-7x+1 (ii) 2x^2+7x+3 (iii) 6x^2+5x-6 (iv) 3x^2-x-4

The series expansion of log[(1 + x)^((1 + x))(1-x)^(1-x)] is (1) 2[(x^(2))/(1.2) + (x^(4))/(3.4)+(x^(6))/(5.6)+...] (2) [(x^(2))/(1.2) + (x^(4))/(3.4)+(x^(6))/(5.6)+...] (3) 2[(x^(2))/(1.2) + (x^(4))/(2.3)+(x^(6))/(3.4)+...] (4) 2[(x^(2))/(1.2) -(x^(4))/(2.3)+(x^(6))/(3.4)-...]