if `6n` tickets numbered 0 1 2 6n-1 are placed in a bag and three are drawn out, show that the chance that the sum of the numbers on them is equal to 6n is `(3n)/((6n-1)(6n-2))`

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,......6n-1 are placed in a bag and three are drawn out,show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

Out of (2n+1) tickets consecutively numbered , three are drawn at random . The chance that the numbers on them are in A.P is

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.