If `p-2^a`, then show that `a^4 +6ap + p^8=0`

If p is the length of perpendicular from the origin on the line (x)/(a) + (y)/( b) =1 and a^(2), p^(2) and b^(2) are in A.P., then show that a^(4) + b^(4) =0 .

If the roots of the equation (q-r)x^(2)+(r-p)x+p-q=0 are equal, then show that p, q and r are in A.P.

If A = ((p,q),(0,1)) the show that A^(8) = ((p^(8),q((p^(8)-1)/(p-1))),(0,1))

The numbers x, 8, y (xney) are in G.P. and the numbers x, y,-8 are in A.P., then show that x = 16, y = 4

If a, b, c are in A.P, then show that: \ b c-a^2,\ c a-b^2,\ a b-c^2 are in A.P.

If p=2-a, prove that a^3+6ap+p^3-8=0

If p=2-a , prove that a^3+6a p+p^3-8=0

If p=2-a , prove that a^3+6a p+p^3-8=0

If p=2-a, prove that a^(3)+6ap+p^(3)-8=0

If A=((p,q),(0,1)) , then show that A^(8)=((p^(8),q((p^(8)-1)/(p-1))),(0,1))