In quadratic equation `x^2+kx+1=0` find range of k for which both roots are `(a) positive` `(b) n e g ative`

For the quadratic equation (k-1)x^(2)-kx+1=0 , find k so that the roots are numerically equal but opposite in sigh.

If roots of quadratic equation x ^2 −kx+4=0 then k will be a. 2 b 1 c. 3 d. 4

One of the roots of quadratic equation 2x^2+kx-2=0 is -2. Find k .

One of the roots of quadratic equation 2x^(2)+kx-2=0 is -2, find k.

If one root of the quadratic equation 2x^(2)+kx-2=0 is -2, find the value of k.

If one root of the quadratic equation 2x^(2)+kx-2=0 is -2, find the value of k.

If one root of the quadratic equation 2x^(2)+kx-6=0 is 2, find the value of k Also,find the other root.

Given the quadratic equation (k-1)x^(2)-kx+1=0 , (where kne1) , find k so that product of the roots is -3.

If x=3 is one root of the quadratic equation x^2-2kx-6=0 , then find the value of k

If one root of the quadratic equation kx^(2) – 7x + 5 = 0 is 1, then find the value of k.