In young's double slit experiment the distance between two sources is`0.1//pimm`.the distance of the screen from the source is `25cm`.wavelength of light used is `5000Å`.Then the angular position of the first dark fringe is-

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young's double slit experiment, the distance between two sources is 0.1mm . The distance of screen from the sources is 20cm . Wavelength of light used is 5460Å . Then angular position of the first dark fringe is

In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is 5460 Å . Then, angular position of first dark fringe is approximately

In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is 5460 Å . Then, angular position of first dark fringe is approximately

In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m . If the fringe width on the screen is 0.06 cm , then lambda =

In the Young's double slit experiment, the spacing between two slits is 0.1mm . If the screen is kept at a distance of 1.0m from the slits and the wavelength of ligth is 5000Å , then the fringe width is