The moment of inertia of a wheel of radius `20 cm` is `40 kgm^(2)` if a tangential force of `80 N` applied on the wheel, its rotational `K.E.` after `4s` is

The moment of inertia of a wheel of radius 20cm is 40kgm^(2) . If a tangential force of 80N applied on the wheel , its Rotational K.E. after 4s is

The moment of inertia of a wheel of radius 10cm is 20kgm^(2) ,If a tangential force of 40N applied on the wheel,its Rotational K.E.after 2s is ?

The moment of inertia of a disc of radius 5 cm is 0.02 "kg.m"^(2) . A tangential force of 20 N is applied along the circumference of the disc. The angular acceleration of the disc will be ( in unit rad .s^(-2) )

The moment of inertia of a wheel is 1000 kg-m^(2) . At a given instant, its angular velocity is 10 rad//s . After the wheel rotates through an angle of 100 radians the wheel's angular velocity is 100 rad//s . Find the torque applied on wheel.

Compute the angular acceleration of a wheel having moment of inertia 20kgm^(2) , when a torque of 10Nm is applied on the wheel.

Compute the angular acceleration of a wheel having moment of inertia 20kgm^(2) , when a torque of 10Nm is applied on the wheel.

Compute the angular acceleration of a wheel having moment of inertia 20kgm^(2) , when a torque of 10Nm is applied on the wheel.