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A wire A , bent in the shape of an arc o...

A wire A , bent in the shape of an arc of a circle , carrying current of 2 and having radius 2 cm and another wire B, also bent in the shape of arc of a circle , carrying a current of 3 A and having radius of 4 cm , are placed as shown in the figure . The ratio of the magnetic fields due to the wires A and B at the common centre O is :

A

`4:6`

B

`6:4`

C

`6:5`

D

`2:5`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A part of a long wire carrying a current i is bent into a circle of radius r as shown in figure. The net magnetic field at the centre O of the circular loop is

    A
    `(mu_(0)i)/(4r)`
    B
    `(mu_(0)i)/(2r)`
    C
    `(mu_(0)i)/(2pir) (pi+1)`
    D
    `(mu_(0)i)/(2pir) (pi-1)`

  • A long wire carrying current 'I' is bent into the shape as shown in the figure. The net magnetic field intensity at the centre 'O' is

    A
    `(mu_(0)I)/(4piR)sqrt(1 + pi^(2))`
    B
    `(mu_(0)I)/(4piR)sqrt(2 + pi^(2))`
    C
    `(mu_(0)I)/(4piR)sqrt(4 + pi^(2))`
    D
    `(mu_(0)I)/(4piR)sqrt(9 + pi^(2))`

  • A wire of length L carrying a current I is bent into a circle. The magnitude of the magnetic field at the centre of the circle is

    A
    `(pi mu_(0)I)/(L)`
    B
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    D
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