Which one of the following represents the correct dimensions of the quantity : `x=(eta)/(rho)`, where `eta`=coefficient of visocosity and `rho` =the density of a liquid?

If D represents the diameter, rho the density , v the speed and eta the coefficient of viscosity , then the quantity (Drhov)/(eta) has :

In dimension of critical velocity v_(c) of liquid following through a tube are expressed as [eta^(x)rho^(y)r^(z)] where eta, rho and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x,y and z are given by

The dimensions of gamma in the relation v = sqrt((gamma p)/(rho)) (where v is velocity, p is pressure , rho is density)

In dimension of circal velocity v_(0) liquid following through a take are expressed as (eta^(x) rho^(y) r^(z)) where eta, rhoand r are the coefficient of viscosity of liquid density of liquid and radius of the tube respectively then the value of x,y and z are given by

In dimension of circal velocity v_(0) liquid following through a take are expressed as (eta^(x) rho^(y) r^(z)) where eta, rhoand r are the coefficient of viscosity of liquid density of liquid and radius of the tube respectively then the value of x,y and z are given by

In dimension of critical velocity v_(c) liquid following through a take are expressed as (eta^(x) rho^(y) r^(z)) where eta, rhoand r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively then the value of x,y and z are given by

In dimension of circal velocity v_(0) liquid following through a take are expressed as (eta^(x) rho^(y) r^(z)) where eta, rhoand r are the coefficient of viscosity of liquid density of liquid and radius of the tube respectively then the value of x,y and z are given by

Derive the folowing relation by the method of dimensions v=sqrt(E/rho) E=coefficient of elasticity, rho =density of medium.