`(x y)/(x-y)=1/2;(x y)/(x+y)=1/5w h e r ex+y!=0; x-y!=0`

(xy)/(x-y)=(1)/(2);(xy)/(x+y)=(1)/(5) wherex +y!=0;x-y!=0

Solve the following system of equations: 1/(2x)-1/y=-1 and 1/x+1/(2y)=9,w h e r e x!=0,y!=0.

Solve for x and y:(xy)/(x+y)=(1)/(5),x+y!=0;(xy)/(x-y)=(1)/(7),x-y!=0

Fill in the blanksIf x<0,y<0,x+y+(x//y)=(1//2)a n d (x+y)(x//y)=-(1//2),t h e nx=___a n dy=___dot

Fill in the blanksIf x<0,y<0,x+y+(x//y)=(1//2)a n d (x+y)(x//y)=-(1//2),t h e nx=___a n dy=___dot

(1+3e^((y)/(x)))dy+3e^((y)/(x))(1-(y)/(x))dx=0 , given that y=0 and x=1

The solution of the differential equation (dy)/(dx)+1=e^(x+y), is (x+y)e^(x+y)=0b(x+C)e^(x+y)=0c*(x-C)e^(x+y)=1d(x-C)e^(x+y)+1=0

If e^(x) + e^(y) = e^(x + y) , then prove that (dy)/(dx) = (e^(x)(e^(y) - 1))/(e^(y)(e^(x) - 1)) or (dy)/(dx) + e^(y - x) = 0 .