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Two capacitors of capacitances 20muF and...

Two capacitors of capacitances 20`mu`F and 60`mu`F are connected in series. If the potential difference between the two ends of the combination is 40 volt, calculate the terminal potential difference of each capacitor.

Text Solution

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In series combination, the charge q on both the capacitors is the same. As V = `(q)/(C )`, we have V `prop (1)/(C )` . Here, ratio between the capacitances = `(20)/(60) = (1)/(3),` so the ratio
between the terminal potential differences = `(3)/(1)`
So, the total voltage of 40V will be distributed as 30V and 10V.
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