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sum(r=0)^(20).^(50-r)C6...

`sum_(r=0)^(20).^(50-r)C_6`

A

`.^(50)C_7-30C_7`

B

`.^(51)C_7-30C_7`

C

`.^(51)C_7+30C_7`

D

`.^(50)C_6-30C_6`

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The correct Answer is:
D
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