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A triangle ABC laying in the first quadr...

A triangle ABC laying in the first quadrant has two vertices as A(1 , 2) B(3 , 1). If , `angle BAC=90^@` and ar `(DeltaABC)=5sqrt5` sq. units , then the abscissa of the vertex C is :

A

`2+sqrt5`

B

`1+2sqrt5`

C

`2sqrt5-1`

D

`1+sqrt5`

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