For shown situation, what will be the magnitude of minimum force in newton that can be applied in any direction so that the resultant force is along east direction?

Answer

6

Explanation

Let force be F so resultant is in east direction
`4hati+3hatj+(5cos 37^(@)hati+5sin 37^(@)hatj)+vecF=kveci`
`rArr 4hati+3hatj+4hati+3hatj+vecF=khatirArr8hati+6hatj+vecF=khati`
`rArrvecF=(k-8)hati-6hatjrArrF=sqrt((k-8)^(2)+(6)^(2))rArrF_("min")=6N`.