Two forces, while acting on particle in opposite directions,have the resultant of 10N. If they act at right angles to each other, the resultant is found to be 50N. Find the two forces?

Explanation

Let the magnitude of forces be A and B such that `AgtB`
then according to question `A-B=10rArrA=10+B`.......(1)
and `sqrt(A^(2)+B^(2))=50rArrA^(2)+B^(@)=2500` .....(2)
Solving equation number (1) `&` (2) `A=40N` and `B=30N`
Therefore the magnitudes forces are `40N & 30N`