What is the value of linear velocity, if vecomega=3hati-4hatj+hatk and vecr=5hati-6hatj+6hatk ?
For a body, angular velocity (vecomega)=hati-2hatj+3hatk and radius vector (vecr)=hati+hatj+hatk , then its velocity:
For a body, angular velocity vecomega= hati-2hatj+3hatk and radius vector vecr=hati+hatj+hatk , then its velocity (vecv= vecomega xx vecr) is :
Show that the line of intersection of the planes vecr*(hati+2hatj+3hatk)=0 and vecr*(3hati+2hatj+hatk)=0 is equally inclined to hati and hatk . Also find the angleit makes with hatj .
If vecF=hati+2hatj-3hatk and vecr=2hati-hatj+hatk find vecrxxvecF
Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.
If vecF=2hati+3hatj-hatk and vecr=hati-hatj+6hatk find vecrxxvecF
Find the shrotest distance between the lines vecr = hati+hatj+ lambda(2hati-hatj+hatk) and vecr= 2hati+hatj-hatk+mu(2hati-hatj+hatk) .
