Dimension of magnetic permeability is :

Options

A. `MLT^(2)A^(-2)`
B. `ML^(-1)T^(-2)A^(-2)`
C. `ML^(-2)T^(-2)A^(2)`
D. `MLT^(2)A^(-2)`

Explanation

Force per unit length between two parallel current carrying wires is given by
`(F)/(l)=(m_(0)I_(1)I_(2))/(2pd)`
`therefore[mu_(0)]=[(F)/(I^(2))]=[(MLT^(2))/(A^(2))]=[MLT^(2)A^(-2)]`