In a particular system the units of length, mass and time are chosen to be `10 cm, 10 g` and `0.1 s` respectively. The unit of force in this system will be equal to

Options

A. 0.1N
B. 1N
C. 10 N
D. 100N

Explanation

`n_(1)u_(1)=n_(2)u_(2)`
`1[kg][m][sec]^(-2)=n_(2)[10gm][10cm][0.1sec]^(-2)`
`n_(2)=1[(1000gm)/(10gm)]^(1)[(100gm)/(10)]^(1)[(sec)/(0.1sec)]^(-2)`
`n_(2)=(1000)/(10^(4))=0.1N`