Force on a particle in one-dimensional motion is given by `F=Av+Bt+(Cx)/(At+D)`, where F= force, v= speed, t= time, x= position and A, B, C and D are constants. Dimension of C will be-

Options

A. `M^(2)L^(-2)T^(0)`
B. `ML^(-1)T(0)`
C. `M^(2)L^(0)T^(-2)`
D. None of these

Explanation

`dim(A)=((F)/(V))rArrdim(C)=dim[(F(At+D))/(x)]`
`=dim[(F)/(x)((Ft)/(v))]=din[(F^(2)t)/(xv)]=dim[F^(2))/(V^(2))]=[M^(2)T^(-2)]`