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The length, breadth and thickness of a s...

The length, breadth and thickness of a sheet are `4.234`m, `1.005` m and `2.01`cm respectively. Give the volume of the sheet to the correct significant figures.

Text Solution

Verified by Experts

length (l)=4.234m breadth (b)=1.005 m
thickness `(t)=2.01 cm=2.01xx10^(-2)m`
Therefore area of the sheet `=2lxxb+bxxt+txxl)`
`=2(4.234xx1.005+1.005xx0.0201+0.0201xx4.234)m^(2)`
`=2(4.3604739)m^(2)=8.720978 m^(2)`
Since area can contain a `"max"^(m)` of 3 SF (Rule II of article 4.2) therefore, rounding off, we get
Area `=8.72 m^(2)`
Like wise volume `=lxxbxxt`
`=4.234xx1.005xx0.0201 m^(3)=0.0855289 m^(3)`
Since volume can contain 3 SF, therefore, rounding off, we get
Volume `=0.0855 m^(3)`
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Knowledge Check

  • The length , breath and thickness of a metal sheet are 4.234m, 1.005m , and 2.01cm respectively then the volume of the sheet is

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    `9.378 m^(2)`
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    D
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