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The resistance R= (V)/(I), where V= (100...

The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage error in `R`.

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`because R=(V)/(I) therefore (DeltaR)/(R)xx100=+-((DeltaV)/(V)+(DeltaI)/(I))xx100=+-[(5)/(100)+(0.2)/(10)]xx100=+-7%`
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