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Two bodies were thrown simultaneously from the same point, one straight up, and the other at an angle of `theta = 30^@` to the horizontal. The initial velocity of each body is `20 ms^(-1)`. Neglecting air resistance, the distance between the bodies at `t = 1.2` later is

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`y=(20xx1.2-(1)/(2)"gt"^(2))-(20 sin 30^(@)xx1.2-(1)/(2)"gt"^(2))=24-12=12m`
`x=20 cos 30^(@)xx1.2=24xxsqrt(3)/(2)rArr12sqrt(3)m`
Distance between two bodies `=sqrt((12)^(2)+(12sqrt(3))^(2))=24m`
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