A wire of `rho_(L)=10^(-6)Omega//m` is turned in the form of a circle of diameter 2m. A piece of same material is connected. In diameter AB. Then find resistance in between A and B.

Explanation

`because R=rho_(L)xx` length.
`therefore R_(1)=pixx10^(-6)Omega,R_(2)=2xx10^(-6)Omega,R_(3)=pixx10^(-6)Omega`
`(1)/(R_(AB))=(!)/(pixx10^(-6))+(1)/(2xx10^(- 6))+(1)/(pi10^(-6))=0.88xx10^(-6)` ohm.