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A battery of six cells each of e.m.f. 2V...

A battery of six cells each of e.m.f. 2V and internal resistance `0.5Omega` is being charged by D.C. mains of e.m.f. 220V by using an external resistance of `10Omega` what will be the charging current.

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Net e.m.f. of the battery =12V and total internal resistance `=3Omega`
Total resistance of the circuit `=3+10=13Omega`
`I=("Net e.m.f.")/("total resistance")=(220-12)/(12)=16A`
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