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The `n` rows each containinig `m` cells in series are joined parallel. Maximum current is taken from this combination across jan external resistance of `3 Omega` resistance. If the total number of cells used are 24 and internal resistance of each cell is `0.5 Omega` then

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Total number of cell mn=24
For maximum current `(mr)/(n)=RrArr0.5m=3n`
`rArrm=(3n)/(0.5)=6n`
`therefore 6 nxxn=24rArrn=2`
and `mxx2=24rArrm=12`
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