When a shunt of `4Omega` is attahced to a galvanometer, the deflection reduces to `(1)/(5)`th. If an additional shunt of `2Omega` is attached. What will be the deflection?

Explanation

Initial condition
When shunt of `4Omega` used
`(1)/(5)xxG=(4)/(5)lxx4rArrG=16Omega`
When additional shunt of `2Omega` used
`I'xx16=(I -I)(4)/(3)`
`12I'=I-I'`
`I'=(I)/(13)` therefore1 it will reduce to `(I)/(13)` of the initial deflaction.