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BALANCED WHEATSTONE BRIDGE

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The correct Answer is:
If deflection is galvenometer is zero then
potential difference across AB=potential difference across AD
`I_(1)P=I_(2)R` .........(i)
Potential diff. across BC=potential diff. across DC
`I_(1)Q=I_(2)S`........(ii)
From equation (i) and (ii) `(I_(1)P)/(I_(1)Q)=(I_(2)R)/(I_(2)S)rArr(P)/(Q)=(R)/(S)`
`(##ALN_PHY_C05_S01_061_A01##)`
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