For the given circuit find out:-

(a) Total resistance of circuit across battery terminals.
(b) Potential difference between A and B.

Explanation

(a)
`R_( "net")=2+(4xx4)/(4+4)+2+9=15Omega`
(b) total current flow in circuit ` =(1//3)/(15)=(1)/(45)A` Apply KVL
`V_(A)-2xx(1)/(45)-r=(1)/(2xx45)-2xx(1)/(45)=V_(B)`
`V_(A)-V_(B)=(2)/(45)+(2)/(45)=(6)/(45)=(6)/(45 )=(2)/(15)=0.133` volt
`V_(AB)=(IxxR "from" A "to" B) =(1)/(45)xx(6)=(6)/(45)=(2)/(15)=0.133V`