The emf E and the internal resistance r of the battery shown in figure are 4.3V and `1.0Omega` respectively. The external resistan ce R is `50Omega`. The resistance of the ammeter and voltameter are `2.0Omega` an d `200Omega` respectively. Find the respective reading of the voltmeter.

Explanation

The equivalen t resistance of parallel combination of R and voltmeter `R_(P)=(50xx200)/(50+200)=50Omega`
Total resistance of circuit `=R_(P)+2+1=40+2+1=43Omega`
Current in the circuit `I=(4.3)/(43)=(1)/(10)=0.1A` Reading of Ameter
Readin g of voltmeter`=0.1xx40=4` volt.