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In fig. battery E is balanced on 55cm le...

In fig. battery E is balanced on 55cm length of potentiometer wire but when a resistance of `10Omega` is connected in parallel with the battery then it balances on 50cm length of the potentiometer wire then internal resistance r of the battery is:-

A

`1Omega`

B

` 3Omega`

C

`10Omega`

D

`5Omega`

Text Solution

Verified by Experts

The correct Answer is:
1
`r=(( l_(0)-l_(C))/(l_(C)))R=((55-50)/(50))10=1Omega`
Here `l_(0)=55cm:l_(c)=50cm:R=10Omega`
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