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AB is a potentiometer wire of length 100...

AB is a potentiometer wire of length 100cm and its resistance is 10ohm. It is connected in series with a resistance R=40 ohm and a battery of e.m.f. wV and negigible internal resistance. If a source of unknown e.m.f. E is balanced by 40cm length of the potentiometer wire, the value of E is:

A

0.8V

B

1.6V

C

0.08V

D

0.16V

Text Solution

Verified by Experts

The correct Answer is:
4
`x=(E)/(R+R_(omega))xx(Romega)/(L_(omega))=(2)/(40+10)xx(10)/(1)=0.4V//m`
`therefore E=xl=0.4xx40xx10^(-2)=0.16V`
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