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N identical cells whether joined togethe...

N identical cells whether joined together in series or in parallel, give the same current, when connected to an external resistance of 'R'. The internal resistance of each cell is:-

A

r=nR

B

r=R

C

`r=(R)/(n)`

D

`r=n^(2)R`

Text Solution

AI Generated Solution

The correct Answer is:
To find the internal resistance of each cell when N identical cells are connected in series or parallel and give the same current through an external resistance R, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Current in Series Connection:** - When N cells are connected in series, the total voltage (E_total) is the sum of the voltages of each cell. Thus, E_total = N * E, where E is the voltage of one cell. - The total internal resistance (r_total) in series is the sum of the internal resistances of each cell: r_total = N * r, where r is the internal resistance of one cell. - The current (I) through the external resistance R can be expressed using Ohm's law: \[ I = \frac{E_{total}}{R + r_{total}} = \frac{N \cdot E}{R + N \cdot r} \] 2. **Understanding the Current in Parallel Connection:** - When N cells are connected in parallel, the voltage across each cell remains the same (E). - The total internal resistance in parallel is given by: \[ r_{total} = \frac{r}{N} \] - The current (I) through the external resistance R can be expressed as: \[ I = \frac{E}{R + r_{total}} = \frac{E}{R + \frac{r}{N}} \] 3. **Setting the Currents Equal:** - Since the current is the same in both configurations, we can set the two equations for current equal to each other: \[ \frac{N \cdot E}{R + N \cdot r} = \frac{E}{R + \frac{r}{N}} \] 4. **Cross-Multiplying to Eliminate Fractions:** - Cross-multiplying gives: \[ N \cdot E \cdot \left(R + \frac{r}{N}\right) = E \cdot \left(R + N \cdot r\right) \] 5. **Simplifying the Equation:** - Cancelling E from both sides (assuming E ≠ 0): \[ N \cdot \left(R + \frac{r}{N}\right) = R + N \cdot r \] - Expanding the left side: \[ N \cdot R + r = R + N \cdot r \] 6. **Rearranging the Equation:** - Bringing all terms involving R and r to one side: \[ N \cdot R - R = N \cdot r - r \] - This simplifies to: \[ (N - 1) \cdot R = (N - 1) \cdot r \] 7. **Dividing by (N - 1):** - Assuming N ≠ 1, we can divide both sides by (N - 1): \[ R = r \] ### Conclusion: The internal resistance of each cell is equal to the external resistance R. ### Final Answer: The internal resistance of each cell is **R**.
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